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Copper(I) chloride

triphenylphosphine: CuCl + 1 P(C6H5)3 → 1/4 {CuCl[P(C6H5)3]}4 CuCl + 2 P(C6H5)3 → CuCl[P(C6H5)3)]2 CuCl + 3 P(C6H5)3 → CuCl[P(C6H5)3)]3 CuCl also forms complexes

Copper(II) chloride

the resultant CuCl back to CuCl2, completing the cycle. C2H4 + PdCl2 + H2O → CH3CHO + Pd + 2 HCl Pd + 2 CuCl2 → 2 CuCl + PdCl2 4 CuCl + 4 HCl + O2 →

Copper

v t e Copper compounds Cu(0,I) Cu5Si Cu(I) CuBr CuCN CuCl CuF CuH CuI Cu2C2 Cu2Cr2O5 Cu2O CuOH CuNO3 Cu3P Cu2S CuS CuSCN C6H5Cu Cu(I,II) Cu4O3 Cu3H4O8S2

Bronze disease

form the insoluble white colored salt cuprous chloride: (2) Cu+ + Cl− → CuCl The cuprous chloride reacts with atmospheric moisture and oxygen to form

Copper–chlorine cycle

+ 2 HCl(g) → 2 CuCl(l) + H2(g) (430–475 °C) 2 CuCl2 + H2O(g) → Cu2OCl2 + 2 HCl(g) (400 °C) 2 Cu2OCl2 → 4 CuCl + O2(g) (500 °C) 2 CuCl → CuCl2(aq) + Cu

Sulfuric acid

FeCl3 + 2 H2O + SO2 → 2 FeCl2 + H2SO4 + 2 HCl 2 CuCl2 + 2 H2O + SO2 → 2 CuCl + H2SO4 + 2 HCl Two less well-known laboratory methods of producing sulfuric

Sandmeyer reaction

chlorination, bromination, cyanation, and hydroxylation reactions using CuCl, CuBr, CuCN, and Cu2O, respectively. More recently, trifluoromethylation

Copper(I) oxide

oxide is attacked by acids. Hydrochloric acid gives the chloride complex CuCl−2. Sulfuric acid and nitric acid produce copper(II) sulfate and copper(II)

Copper(I) acetylide

acetylene with a solution of copper(I) chloride and ammonia: C2H2(g) + 2 CuCl(s) → Cu2C2(s) + 2 HCl(g) This reaction produces a reddish solid precipitate

Tetraamminecopper(II) sulfate

v t e Copper compounds Cu(0,I) Cu5Si Cu(I) CuBr CuCN CuCl CuF CuH CuI Cu2C2 Cu2Cr2O5 Cu2O CuOH CuNO3 Cu3P Cu2S CuS CuSCN C6H5Cu Cu(I,II) Cu4O3 Cu3H4O8S2